Optimal. Leaf size=61 \[ -\frac {(1-2 x)^{3/2}}{55 (5 x+3)}+\frac {64}{275} \sqrt {1-2 x}-\frac {64 \tanh ^{-1}\left (\sqrt {\frac {5}{11}} \sqrt {1-2 x}\right )}{25 \sqrt {55}} \]
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Rubi [A] time = 0.01, antiderivative size = 61, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, integrand size = 22, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.182, Rules used = {78, 50, 63, 206} \begin {gather*} -\frac {(1-2 x)^{3/2}}{55 (5 x+3)}+\frac {64}{275} \sqrt {1-2 x}-\frac {64 \tanh ^{-1}\left (\sqrt {\frac {5}{11}} \sqrt {1-2 x}\right )}{25 \sqrt {55}} \end {gather*}
Antiderivative was successfully verified.
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Rule 50
Rule 63
Rule 78
Rule 206
Rubi steps
\begin {align*} \int \frac {\sqrt {1-2 x} (2+3 x)}{(3+5 x)^2} \, dx &=-\frac {(1-2 x)^{3/2}}{55 (3+5 x)}+\frac {32}{55} \int \frac {\sqrt {1-2 x}}{3+5 x} \, dx\\ &=\frac {64}{275} \sqrt {1-2 x}-\frac {(1-2 x)^{3/2}}{55 (3+5 x)}+\frac {32}{25} \int \frac {1}{\sqrt {1-2 x} (3+5 x)} \, dx\\ &=\frac {64}{275} \sqrt {1-2 x}-\frac {(1-2 x)^{3/2}}{55 (3+5 x)}-\frac {32}{25} \operatorname {Subst}\left (\int \frac {1}{\frac {11}{2}-\frac {5 x^2}{2}} \, dx,x,\sqrt {1-2 x}\right )\\ &=\frac {64}{275} \sqrt {1-2 x}-\frac {(1-2 x)^{3/2}}{55 (3+5 x)}-\frac {64 \tanh ^{-1}\left (\sqrt {\frac {5}{11}} \sqrt {1-2 x}\right )}{25 \sqrt {55}}\\ \end {align*}
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Mathematica [A] time = 0.03, size = 53, normalized size = 0.87 \begin {gather*} \frac {\sqrt {1-2 x} (30 x+17)}{25 (5 x+3)}-\frac {64 \tanh ^{-1}\left (\sqrt {\frac {5}{11}} \sqrt {1-2 x}\right )}{25 \sqrt {55}} \end {gather*}
Antiderivative was successfully verified.
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IntegrateAlgebraic [A] time = 0.12, size = 61, normalized size = 1.00 \begin {gather*} \frac {2 (15 (1-2 x)-32) \sqrt {1-2 x}}{25 (5 (1-2 x)-11)}-\frac {64 \tanh ^{-1}\left (\sqrt {\frac {5}{11}} \sqrt {1-2 x}\right )}{25 \sqrt {55}} \end {gather*}
Antiderivative was successfully verified.
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fricas [A] time = 1.46, size = 59, normalized size = 0.97 \begin {gather*} \frac {32 \, \sqrt {55} {\left (5 \, x + 3\right )} \log \left (\frac {5 \, x + \sqrt {55} \sqrt {-2 \, x + 1} - 8}{5 \, x + 3}\right ) + 55 \, {\left (30 \, x + 17\right )} \sqrt {-2 \, x + 1}}{1375 \, {\left (5 \, x + 3\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 1.25, size = 65, normalized size = 1.07 \begin {gather*} \frac {32}{1375} \, \sqrt {55} \log \left (\frac {{\left | -2 \, \sqrt {55} + 10 \, \sqrt {-2 \, x + 1} \right |}}{2 \, {\left (\sqrt {55} + 5 \, \sqrt {-2 \, x + 1}\right )}}\right ) + \frac {6}{25} \, \sqrt {-2 \, x + 1} - \frac {\sqrt {-2 \, x + 1}}{25 \, {\left (5 \, x + 3\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.01, size = 45, normalized size = 0.74 \begin {gather*} -\frac {64 \sqrt {55}\, \arctanh \left (\frac {\sqrt {55}\, \sqrt {-2 x +1}}{11}\right )}{1375}+\frac {6 \sqrt {-2 x +1}}{25}+\frac {2 \sqrt {-2 x +1}}{125 \left (-2 x -\frac {6}{5}\right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 1.26, size = 62, normalized size = 1.02 \begin {gather*} \frac {32}{1375} \, \sqrt {55} \log \left (-\frac {\sqrt {55} - 5 \, \sqrt {-2 \, x + 1}}{\sqrt {55} + 5 \, \sqrt {-2 \, x + 1}}\right ) + \frac {6}{25} \, \sqrt {-2 \, x + 1} - \frac {\sqrt {-2 \, x + 1}}{25 \, {\left (5 \, x + 3\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 0.06, size = 44, normalized size = 0.72 \begin {gather*} \frac {6\,\sqrt {1-2\,x}}{25}-\frac {2\,\sqrt {1-2\,x}}{125\,\left (2\,x+\frac {6}{5}\right )}-\frac {64\,\sqrt {55}\,\mathrm {atanh}\left (\frac {\sqrt {55}\,\sqrt {1-2\,x}}{11}\right )}{1375} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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sympy [B] time = 108.10, size = 178, normalized size = 2.92 \begin {gather*} \frac {6 \sqrt {1 - 2 x}}{25} - \frac {44 \left (\begin {cases} \frac {\sqrt {55} \left (- \frac {\log {\left (\frac {\sqrt {55} \sqrt {1 - 2 x}}{11} - 1 \right )}}{4} + \frac {\log {\left (\frac {\sqrt {55} \sqrt {1 - 2 x}}{11} + 1 \right )}}{4} - \frac {1}{4 \left (\frac {\sqrt {55} \sqrt {1 - 2 x}}{11} + 1\right )} - \frac {1}{4 \left (\frac {\sqrt {55} \sqrt {1 - 2 x}}{11} - 1\right )}\right )}{605} & \text {for}\: x \leq \frac {1}{2} \wedge x > - \frac {3}{5} \end {cases}\right )}{25} + \frac {62 \left (\begin {cases} - \frac {\sqrt {55} \operatorname {acoth}{\left (\frac {\sqrt {55} \sqrt {1 - 2 x}}{11} \right )}}{55} & \text {for}\: 2 x - 1 < - \frac {11}{5} \\- \frac {\sqrt {55} \operatorname {atanh}{\left (\frac {\sqrt {55} \sqrt {1 - 2 x}}{11} \right )}}{55} & \text {for}\: 2 x - 1 > - \frac {11}{5} \end {cases}\right )}{25} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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